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x^2+6x+9=3-x
We move all terms to the left:
x^2+6x+9-(3-x)=0
We add all the numbers together, and all the variables
x^2+6x-(-1x+3)+9=0
We get rid of parentheses
x^2+6x+1x-3+9=0
We add all the numbers together, and all the variables
x^2+7x+6=0
a = 1; b = 7; c = +6;
Δ = b2-4ac
Δ = 72-4·1·6
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-5}{2*1}=\frac{-12}{2} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+5}{2*1}=\frac{-2}{2} =-1 $
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